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[Solved]: Matrix A is factored in the form PDP^(-1). Use th
Home / Expert Answers / Algebra / matrix-a-is-factored-in-the-form-pdp-1-use-the-diagonalization-theorem-to-find-the-eigenvalues-pa812

(Solved): Matrix A is factored in the form PDP^(-1). Use the Diagonalization Theorem to find the eigenvalues ...



Matrix

A

is factored in the form

PDP^(-1)

. Use the Diagonalization Theorem to find the eigenvalues of

A

and a basis for each eigenspace.

A=[[2,0,-4],[12,6,12],[0,0,6]]=[[-1,0,-1],[0,1,3],[1,0,0]][[6,0,0],[0,6,0],[0,0,2]][[0,0,1],[3,1,3],[-1,0,-1]]

Select the correct choice below and fill in the answer boxes to complete your choice. (Use a comma to separate vectors as needed.) A. There is one distinct eigenvalue,

\lambda =

A basis for the corresponding eigenspace is . B. In ascending order, the two distinct eigenvalues are

\lambda _(1)=

and

\lambda _(2)=

. Bases for the corresponding eigenspaces are {} and {} , respectively. C. In ascending order, the three distinct eigenvalues are

\lambda _(1)=,\lambda _(2)=

, and

\lambda _(3)=

. Bases for the corresponding eigenspaces are



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