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(Solved): Mon Feb 3 HWi Lecture 2 (1/30) Lecture 1 (1/28) *2-24 Determine the magnitude of the resultant force ...
Mon Feb 3 HWi Lecture 2 (1/30) Lecture 1 (1/28) *2-24 Determine the magnitude of the resultant force and it direction, measured counterclockwise from the positive
xaxis
?
fy=Fsin\theta
x:sin45\deg =(f_(1)y)/(200(N)),f_(1)y=sin45\deg (200N)=141N
cos30\deg =(f_(1)x)/(50(N)),f_(1)x=cos30\deg (150N)=130N
f_(x)=\sum f_(x)=141N-130N=11N
y:sin30\deg =(F_(2)x)/(150N),f_(2)x=sin30(150N)=75N
cos45\deg =(f_(24))/(200(N)),f_(2y)=cos45(200N)=141N
x_(y)=\sum fy=141N+75N=216N
R=\sqrt(R_(y)^(2)+R_(x)^(2))=\sqrt((11N)^(2)+(216N)^(2))=216N
tan\theta =