(Solved):   Feed is 3500 kgmol/h please solve it step by step using Cp to calculate Enthalpy A fe ...

 

Feed is 3500 kgmol/h

please solve it step by step ????

using Cp to calculate Enthalpy A feed stream to a evaporation unit contains an equi-molar mixture of benzene and toluene at 10 °C. The vapour stream from the top of the evapbator contains 68.4 mol% benzene at 50 °C and the liquid stream from the bottom contains 40 mol% benzene at 50 °C. Note: You need Cp (benzene, liquid), Cp (toluene, liquid), Cp (benzene vapour), Cp (toluene vapour), latent heat of vaporisation benzene, latent heat of vaporisation toluene.] From Tables C of Benzene; 1. liquid = 1.80 kJ/(kg.K) 2. Vapor 1.09 kJ/(kg.K) H C of Toluene; 1. liquid=1.720 kJ/(kg.K) 2. Vapor 1.126 kJ/(kg.K) = Latent heats; Latent heat of Benzene = 309 kJ/kg Latent heat of Toluene = 351 kJ/kg Boiling points; B.P of Benzene = 80 °C B.P of Toluene 110 °C 53