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(Solved): Please calculate the volume of the body obtained then the area under   above the x-axis bet ...



Please calculate the volume of the body obtained then the area under

\( y=\frac{1}{x^{2} \sqrt{1-(\ln (x))^{2}}} \)

 

above the x-axis between x=e^1/2 and x=e^(sqrt(3))/2 is rotated around the y-axis with details. 

\( y=\frac{1}{x^{2} \sqrt{1-(\ln (x))^{2}}} \)


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Here we have to find the volume of the solid obtained by r
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