(Solved): please help  A proton enters a parallel-plate capactor traveling to the right at a speed of \( ...

A proton enters a parallel-plate capactor traveling to the right at a speed of \( 1.279 \times 10^{-5} \mathrm{~m} / \mathrm{s} \), as shown in the figure. The distance botween the two plates is 1 . ssc cm. The proton anter: electric field between the plates that points downward from the top plate to the bottom plate. Neglecting gravitational forces, what horizontal distance does the proton traverse befor the proton hits the bottom plate?