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(Solved): PYTHON A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes lon ...



PYTHON

A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:

1) The year must be divisible by 4

2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400

Some example leap years are 1600, 1712, and 2016.

Write a program that takes in a year and determines whether that year is a leap year.

Ex: If the input is:

1712

the output is:

1712 - leap year

Ex: If the input is:

1913

the output is:

1913 - not a leap year

\begin{tabular}{l|l}  LAB & 3.29.1: LAB: Leap year \\ ACTIVITY & \end{tabular}
main.py
Load default template...
1 is_leap_yea

\begin{tabular}{l|l} LAB & 3.29.1: LAB: Leap year \\ ACTIVITY & \end{tabular} main.py Load default template... 1 is_leap_year = False input_year = int \( (\operatorname{input}()) \) "' Type your code here. ' ' '


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// Here's your code:- year = int(input()) if (year
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