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(Solved): Q5 (15 pts). Depth-First Search. Given the directed graph above, show the traversal order (e.g., 1, ...


Q5 (15 pts). Depth-First Search. Given the directed graph above, show the traversal order (e.g., \( 1,2,3,4, \ldots \).\( ) w
Q5 (15 pts). Depth-First Search. Given the directed graph above, show the traversal order (e.g., . and (ii) depth-first search starting from 5. Q6 (15 pts). Breadth-First Search. Given the directed graph above, show the traversal order (e.g., 1, 2, 3, 4, ...) when you apply (i) breadth-first search starting from 1 and (ii) breadth-first search starting from 5.


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Here is the implementation of DFS traversal in C++.



void DFS(int node, vector adj[], vector& visited): This function performs a DFS traversal of the graph starting from a given node node. The adjacency list of the graph is passed as adj and a visited vector is used to keep track of which nodes have already been visited.
visited[node] = true; cout << node << " ";: The current node node is marked as visited and printed.
for(int i = 0; i < adj[node].size(); i++): A loop is initiated to traverse through the adjacency list of the current node node.
int neighbor = adj[node][i];: The ith adjacent node of the current node node is accessed using the adjacency list adj.
if(!visited[neighbor]) { DFS(neighbor, adj, visited); }: If the adjacent node neighbor is not yet visited, the DFS function is recursively called on neighbor to continue traversing the graph from that node.
In main():
The number of nodes n and the number of edges m are taken as input.
An adjacency list adj is created and filled up by taking the input for each edge.
A visited vector is created and initialized with false values for each node.
The DFS function is called with the starting node as 1 to perform a DFS traversal of the graph.


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