Question 2 (1 point) V. V? = 100 m/s A?= 1 m² * p = 1.5 MPa Chamber 1.02 MN 0.83 MN m 0.59 MN Nozzle Po = 100 kPa V? = 2000 m/s e A? = 2 m² Ae In a nozzle is stationary, the mass flow through the nozzle is 450 kg/s. The nozzle section is shaped as shown in the figure with all information about the pressure and velocity of the flow at entrance and exit (The given pressures are absolute). The atmospheric pressure is 100 kPa. Calculate the force generated by this nozzle on the nozzle-chamber connection. Pe = 80 kPa Created by Paint X

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Question 2 (1 point) In a nozzle is stationary, the mass flow through the nozzle is

450 kg / s

. The nozzle section is shaped as shown in the figure with all information about the pressure and velocity of the flow at entrance and exit (The given pressures are absolute). The atmospheric pressure is

100 kPa

. Calculate the force generated by this nozzle on the nozzle-chamber connection.

1.02 MN

0.83 MN

0.59 MN

In a nozzle is stationary, the mass flow through the nozzle is

450 kg / s

. The nozzle section is shaped as shown in the figure with all information about the pressure and velocity of the flow at entrance and exit (The given pressures are absolute). The atmospheric pressure is

100 kPa

. Calculate the force generated by this nozzle on the nozzle-chamber connection.

1.02 MN

0.83 MN

0.59 MN

0.95 MN

0.70 MN

0.89 MN

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Expert Answer to - Question 2 (1 point) V. V = 100 m/s A= 1 m * p = 1.5 MPa Chamber 1.02 MN 0.83 MN m 0.59 MN N

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Solution for - Question 2 (1 point) V. V = 100 m/s A= 1 m * p = 1.5 MPa Chamber 1.02 MN 0.83 MN m 0.59 MN N

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This an additional answer to - Question 2 (1 point) V. V = 100 m/s A= 1 m * p = 1.5 MPa Chamber 1.02 MN 0.83 MN m 0.59 MN N

(Solved): Question 2 (1 point) V. V = 100 m/s A= 1 m * p = 1.5 MPa Chamber 1.02 MN 0.83 MN m 0.59 MN N ...

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