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r-1-5k-omega-r-2-8k-omega-r-3-10k-omega-l-10mh-c-1-0-1-mu-f-c-2-0-1-mu-f-ah-s-e-o-s-pa619
(Solved): R_(1)=5k\Omega ,R_(2)=8k\Omega ,R_(3)=10k\Omega ,L=10mH,C_(1)=0.1\mu F,C_(2)=0.1\mu F aH(s)=(E_(o)(s ...
R_(1)=5k\Omega ,R_(2)=8k\Omega ,R_(3)=10k\Omega ,L=10mH,C_(1)=0.1\mu F,C_(2)=0.1\mu F
aH(s)=(E_(o)(s))/(E_(i)(s))
of the circuit in terms of the component values R_(1),R_(2),R_(3),L,C_(1),C_(2).