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(Solved): sample of 120 Arkansas residents and for a random sample of 180 Virginia residents. (a) Formulate hy ...
sample of 120 Arkansas residents and for a random sample of 180 Virginia residents.
(a) Formulate hypotheses that can be used to determine whether the percentage of stay-at-home residents in the two states differs from the overall average of 57.7%.
H_(0):p>0.577
H_(a):p<=0.577
H_(0):p<0.577
H_(a):p>=0.577
H_(0):p>=0.577
H_(a):p<0.577
H_(0):p<=0.577
H_(a):p>0.577
H_(0):p=0.577
H_(a):p!=0.577
(b) Estimate the proportion of stay-at-home residents in Arkansas. (Round your answer to four decimal places.)
Does this proportion differ significantly from the mean proportion for all states? Use \alpha =0.05.
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to four decimal places.)
p-value =
What is your conclusion?
Reject H_(0). There is sufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas differs from the overall proportion of 0.577.
Do not reject H_(0). There is insufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas differs from the overall proportion of 0.577.
Reject H_(0). There is insufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas differs from the overall proportion of 0.577.
Do not reject H_(0). There is sufficient evidence to conclude that the proportion of stay-at-home residents in Arkansas differs from the overall proportion of 0.577.