(Solved): The answer must be in the assembly language using MIPS. Task 3: Division The following MIPS loop ...

The answer must be in the assembly language using MIPS.

Task 3: Division The following MIPS loop computes the gcd of two numbers stored in registers \( \$ \mathbf{a} \boldsymbol{0} \) and \( \$ \mathbf{\$ a 1} \). The result is computed in register \( \$ \mathbf{a} \theta \). Observe the usage of the instruction \( \mathbf{m f h i} \) ! . text .globl main main: li \( \$ a 0,30 \) \#umber a li \( \$ a 1,18 \) \# number b gcd: div \( \$ a 0, \$ a 1 \# \mathrm{HI}= \) remainder, \( \mathrm{LO}= \) quotient move \( \$ a 0, \$ a 1 \# \$ a 0= \) number \( \mathrm{b} \) mfhi \( \$ a 1 \# \$ a 1=a \) b b (remainder) bnez sal, gcd \# loop if (b != 0) li \( \$ v 0,10 \) syscall Modify the above program by asking the user to enter two integers, compute the gcd then display the result.