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(Solved): The bounds of our interval will be <=x<= Thus the volume of the solid obtained when the region ...



The bounds of our interval will be

<=x<=

Thus the volume of the solid obtained when the region bounded by

y=(1)/(2)x^(2)

and

y=2x

is rotated about the line

x=4

is

\int_0^4 2\pi (4-x)(2x-(1)/(2)x^(2))dx=

Try out the following questions, and if you get stuck, check out the videos below. Consider the region bounded by

y=\sqrt(x-4),y=2,x=0

, and

y=0

. Use the shell method to find the volume of the solid obtained when this region is rotated about the

x_(x)

-axis. Consider the region bounded by

y=\root(4)(x)

and

y=\root(3)((x)/(2))

. Use the shell method to find the volume of the solid obtained when this region is rotated about

y=-3

.

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