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[Solved]: The Electric Field Due to a Charged Disk The disk
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(Solved): The Electric Field Due to a Charged Disk The disk has a radius R and a uniform charge density \sigma ...



The Electric Field Due to a Charged Disk The disk has a radius

R

and a uniform charge density

\sigma

. Find the electric field

E

at

P

. Choose

dq

as a ring of radius

r,dq=\sigma dA

Integrate to find the electric field

E

at

P

below. (Step by step to show your work) The Electric Field Due to a Charged Disk The disk has a radius

R

and a uniform charge density

\sigma

. Find the electric field

E

at

P

. Choose

dq

as a ring of radius

r,dq=\sigma dA

dE=(1)/(4\pi \epsi _(o))(dqz)/((z^(2)+r^(2))^((3)/(2)))

Integrate to find the electric field

E

at

P

below. (Step by step to show your work)

E=(\sigma )/(2\epsi _(o))(1-(z)/(\sqrt(z^(2)+R^(2)))), (charged disk)
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