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(Solved): The electric field of a plane electromagnetic pulse in a vacuum is given by E_(z)=E_(0)(a^(2))/(a^(2 ...



The electric field of a plane electromagnetic pulse in a vacuum is given by

E_(z)=E_(0)(a^(2))/(a^(2) (a-ct)^(2))

. What is the corresponding expression for the magnetic field?

B_(y)=(E_(0))/(\epsi lon)(a^(2))/(a^(2)*(z-\epsi lon)^(2))

B_(y)=(2B_(a))/(6)(a)/(a^(2) (a-c)^(2))

B_(1)=(2E_(0))/(6)(a(x-c))/(x^(2) (x-c)^(2))


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