The equilibrium constant for the reaction
Sr(s)+Mg^(2+)(aq)?Sr^(2+)(aq)+Mg(s)
is
1.90\times 10^(29)
at
25\deg C
. Calculate
E^(0)
for a cell composed of
S(r)/(S)r^(2+)
and
M(g)/(M)g^(2+)
half-cells. Be sure your answer has the correct number of significant figures.
?
V
?
110

Question

The equilibrium constant for the reaction

Sr(s)+Mg^(2+)(aq)?Sr^(2+)(aq)+Mg(s)

is

1.90\times 10^(29)

at

25\deg C

. Calculate

E^(0)

for a cell composed of

S(r)/(S)r^(2+)

and

M(g)/(M)g^(2+)

half-cells. Be sure your answer has the correct number of significant figures.

?

V

?

110

Accepted Answer

Expert Answer to - The equilibrium constant for the reaction Sr(s)+Mg^(2+)(aq)Sr^(2+)(aq)+Mg(s) is 1.90 times 10^(29

Answer

Solution for - The equilibrium constant for the reaction Sr(s)+Mg^(2+)(aq)Sr^(2+)(aq)+Mg(s) is 1.90 times 10^(29

Answer

This an additional answer to - The equilibrium constant for the reaction Sr(s)+Mg^(2+)(aq)Sr^(2+)(aq)+Mg(s) is 1.90 times 10^(29

(Solved): The equilibrium constant for the reaction Sr(s)+Mg^(2+)(aq)Sr^(2+)(aq)+Mg(s) is 1.90\times 10^(29 ...