The figure below shows a coaxial cable carrying current $I$ in its inner conductor and a return current of the same magnitude in the opposite direction in the outer conductor. The magnetic field strength at $r = r_{0}$ is $B_{0}$ . Find the ratio $\frac{B}{B _{0}}$ at $r = 2 r_{0}$ and $r = 4 r_{0}$ . (2) (a) $r = 2 r_{0}$ (b) $r = 4 r_{0}$

Question

The figure below shows a coaxial cable carrying current

I

in its inner conductor and a return current of the same magnitude in the opposite direction in the outer conductor. The magnetic field strength at

r = r_{0}

is

B_{0}

. Find the ratio

\frac{B}{B _{0}}

at

r = 2 r_{0}

and

r = 4 r_{0}

. (2) (a)

r = 2 r_{0}

(b)

r = 4 r_{0}

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