The height of a triangle is increasing at a rate of ( 1 mathrm{~cm} / mathrm{sec} ) while the area of the triangle is increasing at a rate of ( 2 mathrm{~cm}^{2} / mathrm{sec} ). At what rate is the base of the triangle decreasing when the altitude of the triangle is ( 10 mathrm{~cm} ) and the area is ( 100 mathrm{~cm}^{2} ). (Hint: solutionspile.com

Question

The height of a triangle is increasing at a rate of  ( 1  mathrm{~cm} /  mathrm{sec}  ) while the area of the triangle is increasing at a rate of  ( 2  mathrm{~cm}^{2} /  mathrm{sec}  ). At what rate is the base of the triangle decreasing when the altitude of the triangle is  ( 10  mathrm{~cm}  ) and the area is  ( 100  mathrm{~cm}^{2}  ). (Hint: The answer is negative. For a triangle,  ( A= frac{1}{2} b h  ) ) solutionspile.com

Accepted Answer

Expert Answer to -   The height of a triangle is increasing at a rate of  ( 1  mathrm{~cm} /  mathrm{sec}  ) while the

Answer

Solution for -   The height of a triangle is increasing at a rate of  ( 1  mathrm{~cm} /  mathrm{sec}  ) while the

Answer

This an additional answer to -   The height of a triangle is increasing at a rate of  ( 1  mathrm{~cm} /  mathrm{sec}  ) while the

(Solved): The height of a triangle is increasing at a rate of \( 1 \mathrm{~cm} / \mathrm{sec} \) while the ...

View Expert Answer

Expert Answer

Buy This Answer $5

Place Order

We Provide Services Across The Globe