The phosphorylation of glucose to glucose 6-phosphate is the initial step in the catabolism of glucose. The direct phosphorylation of glucose by P_(i) is described by the equation Glucose +P_(i)longrightarrow glucose 6-phosphate +H_(2)O, Delta G^('@)=13.8k(J)/(m)ol Calculate the equilibrium constant for the phosphorylation of glucose to glucose 6 solutionspile.com

Question

The phosphorylation of glucose to glucose 6-phosphate is the initial step in the catabolism of glucose. The direct phosphorylation of glucose by

P_(i)

is described by the equation

Glucose +P_(i)longrightarrow glucose 6-phosphate +H_(2)O,\Delta G^('@)=13.8k(J)/(m)ol

Calculate the equilibrium constant for the phosphorylation of glucose to glucose 6-phosphate at

37.0\deg C

.

K_(eq )^('),M^(-1)

In the rat hepatocyte, the physiological concentrations of glucose and

P_(i)

are maintained at approximately

4.8mM

. What is the equilibrium concentration of glucose 6-phosphate (G6P) obtained by the direct phosphorylation of glucose by

P_(i)

?

[G6P]=

 c TOOLS 
x10^(y)

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