(Solved): Type the program's output numbers \( =\{2,4,5,5] \) usex_input - input () ubile, ueer_input 1 - 'e ...

Type the program's output numbers \( =\{2,4,5,5] \) usex_input - input () ubile, ueer_input 1 - 'end't txyl 1. Poosible Valuezrror divitor \( = \) tht \( (u s e t \) _. spet) if divioor \( >701 \) 1 Positible Namefiteor 1) compate (1 in not defined result = condete (result) -lit divieor \( \& \) Of 1. Tabifble thitokltror rend \( \mathrm{t} \) = numbere \( \{ \) divisor \( \} \) 1. Poentble terobledaiontrror renult \( =20-1 \) didivittor prithticeault, ond= \( =1 \) i a 1y Eruncated to an integer except. (Faluetror, Cerotiviatonieror) print \( \left.\right|^{*} t+ \), endes " ? axeepit tiamiertor, tadiezerorit print. 1 ". ' ende' ') usef tiphat \( = \) input:(1) yraikitarty numbert \( =\{2,4,5,8\} \) nser input \( = \) input () While user input \( I= \) 'end's try: 1 Possible ValueError divisor = int (user_input) if divisor \( >20 \) : 1) Pozalble Namekrror - compute () io not detined result - compute (result) elif divisor \( <01 \) 1 Possible Indexertor result \( = \) nurbera \( \{d i v i s o r] \) a18e: 1. Posaible Zerobiviaionkrror result \( =20 \) /l diviaor \( \quad \) I. \( / 1 \) truncatea to an integer print (result, end=+ ') exeept (Valuelirox, ZeroDivistonExror) : print (' \( x \) ', end=' ' ') except (trameError, IndexError): print ( \( { }^{2}+ \) ', ende' ' ' uper input \( = \) tnput () print ('ox')