(Solved): Use the normal distribution to find a confidence interval for a difference in proportions p1p ...

Use the normal distribution to find a confidence interval for a difference in proportions $p_1?p_2$ given the relevant sample results. Assume the results come from random samples, A $99\%$ confidence interval for $p_1?p_2$ given counts of 109 yes out of 550 sampled for Group 1 and 463 yes out 925 sampled for Group 2. Give the best estimate for $p_1?p_2$, the margin of error, and the confidence interval. Round your answers to three decimal places. Bestestimate: Margin of error: Confidence interval: to