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(Solved): Use the relation \( \lim _{\theta \rightarrow 0} \frac{\sin \theta}{\theta}=1 \) to determine the l ...




Use the relation \( \lim _{\theta \rightarrow 0} \frac{\sin \theta}{\theta}=1 \) to determine the limit.
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Use the relation \( \lim _{\theta \rightarrow 0} \frac{\sin \theta}{\theta}=1 \) to determine the limit. \( \lim _{y \rightar
Use the relation \( \lim _{\theta \rightarrow 0} \frac{\sin \theta}{\theta}=1 \) to determine the limit. \[ \lim _{\theta \rightarrow 0} \frac{9 \sin \sqrt{12} \theta}{\sqrt{12} \theta} \] Select the correct answer below and, if necessary, fill in the answer box to complete your choice. A. \( \lim _{\theta \rightarrow 0} \frac{9 \sin \sqrt{12} \theta}{\sqrt{12} \theta}= \) (Type an integer or a simplified fraction.) B. The limit does not exist. Use the relation \( \lim _{\theta \rightarrow 0} \frac{\sin \theta}{\theta}=1 \) to determine the limit. \( \lim _{y \rightarrow 0} \frac{\sin 10 y}{3 y} \) Select the correct choice below and, if necessary, fill in the answer box in your choice. A. \( \lim _{y \rightarrow 0} \frac{\sin 10 y}{3 y}= \) (Type an integer or a simplified fraction.) B. The limit does not exist.


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