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(Solved): Using matlab code. solve initial value problem by the backward Euler method. we use previous step's ...



Using matlab code. solve initial value problem by the backward Euler method. we use previous step's value for solving implicit equation by newton's method.

Please fill in the blank. (3 blank)

f = @ (t,y) -y^3 - 1/2*y;
y_init = 1;
a = 0; b = 3; n =60;
h = [blank 1];
t = a; y = y_init;
fv = zeros (1, n+1);
fv(1) = y_i

f = @ (t,y) -y^3 - 1/2*y; y_init = 1; a = 0; b = 3; n =60; h = [blank 1]; t = a; y = y_init; fv = zeros (1, n+1); fv(1) = y_init; i = 1; fprintf("t=0.00x6fla", y_init); while i <= n t = t+h; y = [blank 2 ]; fprintf("t=.6f\n", t,y); i=i+1; fv(i) = y; end function sol = newtonsolve(y,h) a = y; b = [blank 3 -1 ]; while abs(b-a) > 0.00001 a = b; b = [blank 3-2 ]; end sol = b; end


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Question: Solution: Using matlab code. Backward Euler's method f = @ (t,y) -y^3 - 1/2*y; y _ init = 1; a = 0; b = 3; n = 60; h
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