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(Solved): vA(t)=arctan(7t)vB(t)=ln(6t)vC(t)=e9tvD(t)=4+t2 Which of these cars travelled ...



\[
\begin{array}{l}
v_{A}(t)=\arctan (7 t) \\
v_{B}(t)=\ln (6 t) \\
v_{C}(t)=e^{-9 t} \\
v_{D}(t)=\sqrt{4+t^{2}}
\end{array}

Which of these cars travelled further during the time interval Your answer: Car A Car Car C Car D


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