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(Solved): What is the acid buffering capacity (the maximum moles of strong acid allowed) of a \( 2.00 \) lite ...
What is the acid buffering capacity (the maximum moles of strong acid allowed) of a \( 2.00 \) liter buffered solution containing \( 0.400 \mathrm{M} \mathrm{HF} \) and \( 0.250 \mathrm{M} \mathrm{NaF} \) ?
Expert Answer
Answer : as per the Henderson–Hasselbalch equation pH = pKa + log [ NaF]/[HF] pH1 = pKa + log [0.25] / [0.4] ............1 mole of NaF = concentration of NaF * volume in (L) = 0.250*2.00 = 0.500 mole mole of HF = concentration of NaF * volume in (L)