y_(i+1)=y_(i)+[(1)/(3)k1+(2)/(3)k2]h k1=f(\xi ,yi) k2=f(\xi +(3)/(4)h,yi+(3)/(4)k1h)
(5 Marks) (b) Solve the above function using Laplace transform method. Construct a table to compare
x
and
y
values at each step with step size
h
. (5 marks)