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(Solved): You are exploring a newly discovered planet. The radius of the planet is 6.90107m. You suspend a l ...



You are exploring a newly discovered planet. The radius of the planet is 6.90×107m. You suspend a lead weight from the lower end of a light string that is 4.00 m long and has mass 0.0280 kg. You measure that it takes 0.0675 s for a transverse pulse to travel from the lower end to the upper end of the string. On earth, for the same string and lead weight, it takes 0.0400 s for a transverse pulse to travel the length of the string. The weight of the string is small enough that its effect on the tension in the string can be neglected. Assuming that the mass of the planed is distributed with spherical symmetry, what is its mass? Please include units in answer.



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Given : Radius of planet   ,
Length of string   ,
Mass of lead weight   ,
Wave travel time on the other planet   ,
Wave travel time on Earth   .

Now,
  , is the mass per unit length of the string,
For other planet,
  Velocity of the wave   m/s,
And, we can use the equation for the speed of a transverse wave on a string:
  , here T is the tension in the string
T will be equal to the weight of the lead ball.
  ,
  .
Hence,
  , here gp is the acceleration due to gravity at that planet,
  

The equation of speed of traverse wave in a string is used.



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