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(Solved): You have a light spring which obeys Hooke's law. This spring stretches 2.88 cm vertic ...



You have a light spring which obeys Hooke's law. This spring stretches 2.88 cm vertically when a 3.00 kg object is suspended from it. Determine the following.

he force constant of the spring (in N/m)

the distance (in cm) the spring stretches if you replace the 3.00 kg object with a 1.50 kg object

the amount of work (in J) an external agent must do to stretch the spring 6.80 cm from its unstretched position

 

 



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Apply Hooks law to find the force constant of the spring. Expression for Hook's law, F=kxk=Fx=mgx=(3.0kg)(9.8ms2)2.88×10?2m=1,020.83Nm
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